Electrolysis Practice Exam

How much of a 10% active ingredient is needed to create a 1000 ppm Quat. Ammonium Compound?

1. 1 oz. per gallon of water

2. 1 1/4 oz. per gallon of water

3. 1 2/3 oz. per gallon of water

4. 2 oz. per gallon of water

The correct answer is: 1 1/4 oz. per gallon of water

To determine how much of a 10% active ingredient is required to produce a 1000 ppm (parts per million) concentration of Quat. Ammonium Compound, it is essential to understand the relationship between percent solutions and ppm. A 10% solution means that there are 10 grams of active ingredient in every 100 milliliters of solution. To convert ppm to a more comparable scale, 1000 ppm can also be expressed as 1000 mg per liter or 1 gram per liter. Since there are approximately 3785 milliliters in a gallon, to achieve 1 gram per gallon of solution using a 10% concentration, we can set up the following calculations: 1. To find the volume of the 10% solution needed to obtain 1 gram of active ingredient: - A 10% solution contains 10 grams in 100 mL. - Therefore, to find out how much of this solution contains 1 gram of active ingredient, the formula is: \[(\text{Volume}) \times 0.10 = 1 \text{ gram}\] - Simplifying gives: \[\text{Volume} = \frac{1 \text{